Consider x^2-64. Rewrite x^2-64 together x^2-8^2. The distinction of squares have the right to be factored making use of the rule: a^2-b^2=\left(a-b\right)\left(a+b\right).

You are watching: 16^2x+1=128


*

2x2-128=0 Two services were found : x = 8 x = -8 step by step solution : step 1 :Equation in ~ the finish of action 1 : 2x2 - 128 = 0 step 2 : action 3 :Pulling out prefer terms : 3.1 pull ...
12x2-12=0 Two solutions were found : x = 1 x = -1 step by step solution : action 1 :Equation at the finish of step 1 : (22•3x2) - 12 = 0 action 2 : action 3 :Pulling out like terms : 3.1 ...
32x2-18=0 Two solutions were uncovered : x = 3/4 = 0.750 x = -3/4 = -0.750 action by step solution : step 1 :Equation at the finish of action 1 : 25x2 - 18 = 0 step 2 : action 3 :Pulling out favor ...
4x2-128=0 Two remedies were found : x = 4 • ± √2 = ± 5.6569 action by action solution : action 1 :Equation in ~ the end of action 1 : 22x2 - 128 = 0 action 2 : step 3 :Pulling out ...
8x2-128=0 Two solutions were discovered : x = 4 x = -4 step by action solution : action 1 :Equation at the end of step 1 : 23x2 - 128 = 0 action 2 : action 3 :Pulling out choose terms : 3.1 traction ...
2x2-121=0 Two services were discovered : x = ±√ 60.500 = ± 7.77817 action by action solution : step 1 :Equation in ~ the finish of action 1 : 2x2 - 121 = 0 action 2 :Trying to element as a ...
More Items
*
*

*
*
*

Consider x^2-64. Rewrite x^2-64 as x^2-8^2. The distinction of squares deserve to be factored using the rule: a^2-b^2=\left(a-b\right)\left(a+b\right).
Quadratic equations prefer this one, v an x^2 term but no x term, can still be resolved using the quadratic formula, \frac-b±\sqrtb^2-4ac2a, as soon as they are placed in standard form: ax^2+bx+c=0.

See more: 2003 Saturn L200 Fuel Pump Replacement Cost Estimate, Fuel Pumps For Saturn L200 For Sale


This equation is in typical form: ax^2+bx+c=0. Substitute 2 for a, 0 because that b, and also -128 for c in the quadratic formula, \frac-b±\sqrtb^2-4ac2a.
\left< \beginarray together l 2 & 3 \\ 5 & 4 \endarray \right> \left< \beginarray together l l 2 & 0 & 3 \\ -1 & 1 & 5 \endarray \right>
*
*

*
*

EnglishDeutschEspañolFrançaisItalianoPortuguêsРусский简体中文繁體中文Bahasa MelayuBahasa Indonesiaالعربية日本語TürkçePolskiעבריתČeštinaNederlandsMagyar Nyelv한국어SlovenčinaไทยελληνικάRomânăTiếng Việtहिन्दीঅসমীয়াবাংলাગુજરાતીಕನ್ನಡकोंकणीമലയാളംमराठीଓଡ଼ିଆਪੰਜਾਬੀதமிழ்తెలుగు