An interior explosion division an object, at first at rest, into two pieces, among which has actually 1.6 time the fixed of the other.If 6300 JJ were released in the explosion, just how much kinetic energy did each piece acquire?
Express her answers utilizing two far-ranging figures. Go into your answers numerically be separated by a comma.
You are watching: An internal explosion breaks an object initially at rest into two pieces
m1, v1 be the mass and also speed that one piece,
m2, v2 it is in the mass and speed that the various other piece,
E = 6300 J be the complete energy,
E1 = m1v1²/2 it is in the power of the an initial piece,
E2 = m2v2²/2 it is in the power of the other piece,
r = m1/m2 = 1.6 be the ration in between the masses.
m2 = m1/r
By conservation of momentum
m1v1 = m2v2
Therefore we deserve to write
v2 = m1v1/m2 = rv1
E2 = (m1/r)(rv1)²/2 = rm1v1²/2 = rE1
By conservation of energy
E = E1 + E2 = E1 + rE1 = E1(1+r)
E1 = E/(1+r)
Plugging in actual numbers
E1 = 6300/2.6 = 2423 J
E2 = E - E1 = 6300 - 2423 = 3877 J
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