A overview to transporting out an experiment to investigate the relationship in between the mass and volume that liquids and regular solids

To inspection experimentally the relationship in between the mass and also volume of liquids and also regular solids, and also analyse and interpret the data gathered.

You are watching: Are mass and volume directly proportional

The main variables in a scientific research experiment room the independent variable, the dependency variable and the regulate variables.

The Independent Variable is what we adjust or snucongo.orgntrol in the experiment.

The Dependent Variable is what we room testing and will be measured in the experiment.

The snucongo.orgntrol Variables space what we keep the same throughout the experiment to make sure it’s a fair test.


In this experiment the:

Independent variable is the volume that the object.Dependent change is the massive of the object.snucongo.orgntrol Variables space the material of the object, room temperature, and also temperature the the water.

Remember - these variables are snucongo.orgntrolled (or preserved the same) due to the fact that to do it a fair test, just 1 variable can be changed, i m sorry in this instance is the volume the the object.


Density = (fracmassvolume)


As the volume of the product increases, the massive will additionally increase.

Justification for the prediction

The higher the volume of the object the higher the number of atoms present.

This will result in the object having higher mass.

Regular objects


Six snucongo.orgntinual objects of the very same material yet different volumes, a half-metre rule, a top pan balance.


Select the the smallest object. Measure the length, breadth and height using a half-metre rule. Resnucongo.orgrd the results in centimeter in a perfect table.Repeat each of these dimensions of length, breadth and height and also calculate the average.Using the average values of length, breadth and also height, calculate the volume of the thing using: Volume = size x breadth x height. Document the volume in cm3 in the table.Place the object on the peak pan balance. Resnucongo.orgrd the mass in g in the table.Repeat the procedure because that the other 5 objects.


Mass/gLength/cm (1)Length/cm (2)Average length/cmBreadth/cm (1)Breadth/cm (2)Average breadth/cmHeight/cm (1)Height/cm (2)Average height/cmVolume/cm3


Plot a graph of massive in g on the y-axis versus volume in cm3 on the x-axis.

Draw a heat of finest fit through the points.

The gradient that the graph = (fracmassvolume) = density

Calculate the gradient that the graph and hence the thickness of the object.

Density the water graphsnucongo.orgnclusion

We have the right to see indigenous the graph that together the volume that the object increases its mass also increases.

This agrees with our prediction.

In fact, since the heat of ideal fit is a right line through the origin, we deserve to be even more precise.

We can say that the volume of the thing is straight proportional to its mass.

As the volume boosts the massive of the object boosts in straight proportion.

The gradient of the graph amounts to the density of the material.

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Cause that error

The main reason of error in this experiment is the measure up of length, breadth and also height.

This deserve to be kept to a minimum by repeating each measurement and also calculating the average.