For the feasibility region shown below (will connect in a sec!!), uncover the maximum value of the role P=2x+3y.*** there space no answer choices...

9 years earlierOpenStudy (anonymous):9 years ago

OpenStudy (anonymous):

hi!!! i have like no idea just how to perform this :(

9 years agojimthompson5910 (jim_thompson5910):

this is a straight programming problem

9 years agojimthompson5910 (jim_thompson5910):

so very first you need to recognize the edge points

9 years agojimthompson5910 (jim_thompson5910):

what room the corner points

9 years agojimthompson5910 (jim_thompson5910):

the min and also the max will an outcome if you plug in among those points into P = 2x+3y

9 year agojimthompson5910 (jim_thompson5910):

plug in (0,0) p = 2x+3y p = 2(0)+3(0) ns = 0 + 0 ns = 0 plugin (0,8) ns = 2x+3y ns = 2(0)+3(8) ns = 0 + 24 ns = 24

9 year agojimthompson5910 (jim_thompson5910):

So we have actually the following(0,0) ---> p = 0(0,8) ---> ns = 24(6,5) ---> ns = 27(8,0) ---> p = 16which allude yields the biggest value the P?

9 years agojimthompson5910 (jim_thompson5910):

so the max of ns = 2x+3y is ns = 27 given the limitations in the graph

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KyledaGreat:x = 2|y| - 1 uncover four points contained in the inverse. Refer your values as an essence or simplified fraction.

You are watching: For the feasibility region shown below, find the maximum value of the function

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SkyIsDumb:Triangle PQR is changed to triangle P"Q"R". Triangle PQR has vertices P(4, 0), Q(0, u22124), and also R(u22128, u22124).

SkyIsDumb:Triangle PQR is revolutionized to triangle P"Q"R". Triangle PQR has actually vertices P(4, 0), Q(0, u22124), and also R(u22128, u22124).

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