For the feasibility region shown below (will connect in a sec!!), uncover the maximum value of the role P=2x+3y.*** there space no answer choices...
9 years earlierOpenStudy (anonymous):9 years ago
OpenStudy (anonymous):
hi!!! i have like no idea just how to perform this :(
9 years agojimthompson5910 (jim_thompson5910):
this is a straight programming problem
9 years agojimthompson5910 (jim_thompson5910):
so very first you need to recognize the edge points
9 years agojimthompson5910 (jim_thompson5910):
what room the corner points
9 years agojimthompson5910 (jim_thompson5910):
the min and also the max will an outcome if you plug in among those points into P = 2x+3y
9 year agojimthompson5910 (jim_thompson5910):
plug in (0,0) p = 2x+3y p = 2(0)+3(0) ns = 0 + 0 ns = 0 plugin (0,8) ns = 2x+3y ns = 2(0)+3(8) ns = 0 + 24 ns = 24
9 year agojimthompson5910 (jim_thompson5910):
So we have actually the following(0,0) ---> p = 0(0,8) ---> ns = 24(6,5) ---> ns = 27(8,0) ---> p = 16which allude yields the biggest value the P?
9 years agojimthompson5910 (jim_thompson5910):
so the max of ns = 2x+3y is ns = 27 given the limitations in the graph
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You are watching: For the feasibility region shown below, find the maximum value of the function

SkyIsDumb:Triangle PQR is changed to triangle P"Q"R". Triangle PQR has vertices P(4, 0), Q(0, u22124), and also R(u22128, u22124).
SkyIsDumb:Triangle PQR is revolutionized to triangle P"Q"R". Triangle PQR has actually vertices P(4, 0), Q(0, u22124), and also R(u22128, u22124).
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