The worth for Avogadro"s number is 6.022 x 10^23 molecules/molTo obtain the number of moles of NH3 native 1.50 x 10^23 molecules of NH3, we will simply solve like this;(1.50 x 10^23 molecules) ÷ 6.02 x 10^23 molecules/mol = 2.49 x 10^22 mol NH3Therefore, the number of moles that NH3 is 2.49 x 10^23.

Consider the reaction once aqueous options of potassium hydroxide and also ammonium nitrate space combined. The net ionic equation fo

snucongo.org: Explanation:

A double displacement reaction is one in i beg your pardon exchange of ion take place. The salts which are soluble in water room designated by symbol (aq) and those which are insoluble in water and remain in solid form are stood for by (s) after your chemical formulas.

You are watching: How many moles is 1.50x10^23 molecules of nh3 The equation have the right to be written in terms of ions as: Spectator ions are defined as the ion which does not get affiliated in a chemical equation or they are ions i beg your pardon are found on both the political parties of the chemistry reaction existing in ionic form.

The ion which are existing on both the sides of the equation room potassium and also nitrate ions and also hence space not affiliated in net ionic equation.

Hence, the network ionic equation is : 6 0
1 year ago

What is the early reactant for a blend reaction in the sun? a) Iron-56b) Hydrogen-1
jarptica <38.1K>

Hydrogen

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6 0
4 month ago

Plz help I don’t acquire this and also if acquire this ideal u gain 70 points
belka <17>

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13. Nervous and Integumentary 14. Digestive and also Excretory

Explanation:

4 0
1 year ago

According come the VSEPR model, the plan of electron pairs around NH3 and also CH4 is A. The same, because in each case there ar

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Option "B" is correct.

Explanation:

According come VSEPR theory, There space repulsion forces exists among the link pair - bond pair or link pair - lone pair the electrons. In and also , the number of electron pairs space same however methane has all the four bond pairs whereby in ammonia, three bond pairs and also one lone pair exists. And thus there space repulsion forces feasible in between the lone pair and bond pair that electrons therefore the arrangement of electron pairs about both the molecules is very same or different depending up on the conditions leading come maximum repulsion.

3 0
1 year ago
What is the brand-new solution concentration when 150. ML that water is added to 200. ML the a 3.55 M HBr solutions.

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Agata <3.3K>

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The brand-new concentration is 2.03M

Explanation:

Step 1: Data given

A 200 mL 3.55 M HBr is diluted with 150 mL

Step 2: The dilution

In a dilution, the ratio that exists in between the concentration the the share solution and also the concentration of the diluted solution equals the proportion that exists in between the volume the the diluted solution and also the volume the the stock solution.

Dilution aspect = / = diluted volume / share volume

In this case, the volume that the stock equipment is 200 mL

Adding 150 mL the water to the stock systems will dilute it come a final volume the 200 + 150 = 350 mL

The dilution aspect wll be 350/200 = 1.75

This renders the diluted concentration:

3.55/1.75 = 2.03M

The new concentration is 2.03M

3 0
9 months ago
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