### Reformatting the input :

Changes made to your input should not influence the solution: (1): "x3" was replaced by "x^3".

You are watching: How to factor x^3 - 8

## Step 1 :

Trying to factor as a distinction of Cubes:

1.1 Factoring: x3-8 theory : A distinction of 2 perfect cubes, a3-b3 have the right to be factored into(a-b)•(a2+ab+b2)Proof:(a-b)•(a2+ab+b2)=a3+a2b+ab2-ba2-b2a-b3 =a3+(a2b-ba2)+(ab2-b2a)-b3=a3+0+0+b3=a3+b3Check:8is the cube the 2Check: x3 is the cube that x1Factorization is :(x - 2)•(x2 + 2x + 4)

Trying to factor by dividing the middle term

1.2Factoring x2 + 2x + 4 The very first term is, x2 that is coefficient is 1.The middle term is, +2x that is coefficient is 2.The last term, "the constant", is +4Step-1 : multiply the coefficient that the first term by the continuous 1•4=4Step-2 : discover two determinants of 4 who sum equates to the coefficient that the middle term, i m sorry is 2.

 -4 + -1 = -5 -2 + -2 = -4 -1 + -4 = -5 1 + 4 = 5 2 + 2 = 4 4 + 1 = 5

Observation : No 2 such components can be uncovered !! Conclusion : Trinomial have the right to not it is in factored

## Final result :

(x - 2) • (x2 + 2x + 4)

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