Since

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,If we adjust one of the variables, (P, V, n, or T) climate one or more oftheother variables must also change. Thisleads come the equation
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or if the variety of moles remains thesame
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.

You are watching: P1v1/t1=p2v2/t2 solve for p2

Boyle"s Law:

Boyle"s legislation examines the result of changing volume on Pressure.To isolate these variables, temperature need to remain constant.We can remove temperature from both sides of the equation andwe areleft through P1V1= P2V2

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Sample Problem: A pistonwith a volume the gas that 1.0 m3 at 100 kPa is compressed come afinalvolume that 0.50 m3. Whatis the last pressure?

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P1 is 100 kPa

V1 is 1.0 m3

V2 is 0.50 m3

P2 is unknown

P1V1=P2V2 becomes
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See an computer animation on rearranging the merged gas lawCharles"s Law

Charles"s law examines the effect of changingtemperatureon volume. Come isolate these variables, pressure must remain constant.

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so Charles"s legislation is
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Sample problem: A piston through a volume the gas of1.0 m3at 273 K is cooled come a temperature of 136.5 K. Whatis the final volume? (Assume pressure is kept constant.)

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T1 is 273 K

V1 is 1.0 m3

V2 is unknown

T2 is 136.5 K

Thesolution i do not care
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Charleslaw Applet watch what happens once you increasetemperature.Increasing temperature __________ pressure.

GUY-LUSSAC"S LAWNear the turn of the 19th century, Guy-Lussac investigated therelationship in between pressure and temperature if the volume to be heldconstant. When the temperature goes up the pressure inside arigid container likewise goes up. Because that example, your car tires, wheninflated, are essentially rigid, the volume will certainly not change. Didyou notice that when the temperature goes increase the pressure inside yourtires also increases?We deserve to again use the linked gas regulation to quantify this relationship.

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Sample Problem: If yourtire is 2 liters and the initial press is 2 atm, what is the finalpressure once the temperature goes from 0 degrees celcius (273 K) to100 degrees celcius (373 K)?

T1 is 273 KP1 is 2 atmP2 is unknownT2 is 373 K

First, begin with the combinedgas law and cancel the end the volumes because they carry out not change.

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After remove the volumes,
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Rearranging the equation:
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so the last pressure P2, is (2.00atm)(373K)/(273 K) = 2.73 atm