The chemical formula for diamminedichloroethylenediaminecobalt(III) bromide is #<"CoCl"_2("en")("NH"_3)_2>"Br" # , whereby (en) is the symbol because that ethylenediamine, #"H"_2"N-CH"_2"-CH"_2"-NH"_2"#. I mean it can be created as #"CoC"_2"H"_14"N"_4"Cl"_2"Br"#, however I didn"t check out that in my research. The name literally way <"two ammonia"-"two chlorine"-"ethylene two amine"-"cobalt (III)"> bromide.

I uncovered four isomers the the diamminedichloroethylenediaminecobalt(III) ion on one more pdf document at . They space on web page 5. Friend would just need to add the #"Br"^-"# ion. The formula is created in a various order as #"^+#, which ns think is a much better way to create it, despite this to be the only ar I experienced it created that way.

You are watching: What is the chemical formula for cobalt(iii) bromide?

Answer connect

Stefan V. · Meave60

See more: What Is A 1927 Buffalo Nickel Worth ? 1927 S Buffalo Nickel Value

may 25, 2015

I"m not fully sure around the isomers, so I"ll just assist you v the formula now and maybe upgrade the answer morning after I"m certain I have all the 9 isomers you mentioned.

So, you"re managing a coodination complex, which is composed of a main metal atom, in your instance cobalt, #Co#, surrounding by a variety of ligands.

Notice that the name of the compound consists of the cobalt (III) ion, or #Co^(3+)#. This will help you check how numerous ligands surround the main cobalt atom.

The electron construction of cobalt looks choose this

#"Co": <"Ar"> 4s^(2) 3d^(7)#

Since cobalt is a transition metal, every the electrons situated outside its noble gas core are taken into consideration to be valence electrons. The electron configuration of the #Co^(3+)# cation will certainly be

#"Co"^(3+): <"Ar"> 3d^(6)#

A low spin facility such together this one will have these 6 valence electrons paired in 3 of the 5 3d-orbitals, and also use the remaining two 3d-orbitals, the 4s-orbital, and also the 3 4p-orbitals to kind 6 #d^2sp^3# hybrid orbitals.

These hybrid orbitals will accomodate the electron pairs the come from the ligands.

So, you need to include six ligands to your central cobalt atom. According to the created formula, these ligands will be

Two chlorine atoms - this originates from dichloroTwo ammine sensible groups - this originates from diammineOne ethylenediamine (abbreviated en).

You only require one ethylenediamine because its structure looks prefer this


The two #"-NH"_2# teams will each tie to one of cobalt"s six easily accessible electrons. Due to the fact that the link is a bromide, the charge on the coordination facility will be +1, in order come balance the -1 charge of the bromide anion, #Br^(-)#.