When we"re looking at the LCM (Least typical Multiple), we"re in search of a number the both 12 and 15 space a factor of. Oftentimes world simply assume that if us multiply the two together, we"ll find it. In this case, it"d be #12xx15=180#. 180 is a lot of of both, yet is the the least one? Let"s look.

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#12=2xx2xx3#

#15=3xx5#

To find the LCM, we desire to have all the prime components from both number accounted for.

For instance, there are two 2s (in the 12). Let"s placed those in:

#LCM=2xx2xx...#

There is one 3 in both the 12 and also the 15, therefore we need one 3:

#LCM=2xx2xx3xx...#

And over there is one 5 (in the 15) therefore let"s put that in:

#LCM=2xx2xx3xx5=60#

#12xx5=60##15xx3=60#

sjc
jan 30, 2018

#60#

Explanation:

another approach is to use teh relation

#ab=hcf(a,b)lcm(ab)#

now #hcf(12,15)=3#

#:.12xx15=3xxlcm(12,15)#

#lcm(12,15)=(cancel(12)^4xx15)/cancel(3)#

#lcm=4xx15=60#

Meave60
Feb 1, 2018

The LCM is #60#.

Explanation:

The LCM is the least common multiple. Us can find the LCM by listing the multiples that the two numbers and identifying the shortest multiple they have actually in common.

#12:##12,24,36,48,color(red)60,72,84...#

#15:##15,30,45,color(red)60...#

The LCM is #60#.

Parabola
Feb 1, 2018

#60#

Explanation:

Let"s try to uncover the LCM of #12# and #15#.

We get: #12=2*2*color(blue)3##15= color(blue)3*5#

We view that they both share #3# is their LCM.

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We divide each number by their LCM.

#12/3=>4#

#15/3=>5#

We multiply these two quotients and the LCM to gain our last answer:

#3*4*5=60#