I have actually tried to recognize what the oxidation state because that Mn in $ceMnO4^-$ is. So far i have construed that O have the oxidation state of -2 so because there is 4 O the number turns to -8. What wake up to the minus in ~ O? and also what is the oxidation state because that Mn?


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The amount of the oxidation claims of all of the atoms requirements to equal the total charge ~ above the ion.

You are watching: What is the oxidation number of mn in a permanganate anion?

For example, for $ceNH4+$, if every hydrogen atom has an oxidation state that +1, and the overall charge is +1, climate we can solve because that the oxidation state the nitrogen:

$$eginaligned 4(+1) + OS_ceN &= +1\OS_ceN &= +1 -4(+1) \OS_ceN &= -3endaligned$$

Similarly, we can do $ceSO4^2-$. If every oxygen atom has an oxidation state of -2, and also the as whole charge is -2, we deserve to solve for the oxidation state of sulfur:

$$eginaligned 4(-2) + OS_ceS &= -2\OS_ceS &= -2 -4(-2) \OS_ceS &= +6endaligned$$


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answered jan 6 "19 in ~ 12:28
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Ben NorrisBen Norris
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Seeing together Oxygen has actually an oxidation state the -2 and you have 4 Oxygen atoms, the full charge contributed by Oxygen = -8. Because the full charge that this compound = -1, then in this situation Mn = +7+7 - 8 = -1


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answered january 6 "19 in ~ 13:32
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PeteLDWPeteLDW
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As you claimed Oxygen has the oxidation state the -2 so if we add up all the oxygens they have a -8 oxidation state.

As the oxidation state of the ion is equal to that is charge, the Mn has to "balance" the -8 to acquire it up to -1. Thus the oxidation state that Mn in Mno4- is +7.


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answered jan 6 "19 at 13:33
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LR01LR01
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